8f7f082c3d
- 重构项目目录结构,将功能模块移至 modules/ 目录 - 创建平台同步基础架构,包括发布器基类和 GitHub 发布器 - 新增 UI 状态管理模块 (modules/ui/state.py) 统一管理会话状态 - 更新依赖配置,添加平台同步所需依赖 (httpx, pyperclip) - 整理文档结构,将所有文档分类移至 docs/ 目录 - 添加 .cursorrules 文件定义项目开发规范 - 清理根目录重复文件,保持项目结构整洁
51 lines
1.4 KiB
Python
51 lines
1.4 KiB
Python
"""
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移动重组相关文档到 docs/guides/ 目录
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"""
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from pathlib import Path
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import shutil
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# 项目根目录
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root = Path(__file__).parent
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# 需要移动的重组相关文档
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reorganization_docs = [
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"DOCUMENTATION_CLEANUP_GUIDE.md",
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"PROJECT_STRUCTURE_ANALYSIS.md",
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"QUICK_REORGANIZE.md",
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"REORGANIZATION_SUMMARY.md",
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]
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# 目标目录
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target_dir = root / "docs" / "guides"
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target_dir.mkdir(parents=True, exist_ok=True)
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def move_reorganization_docs():
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"""移动重组相关文档到 docs/guides/"""
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moved_count = 0
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print("开始移动重组相关文档到 docs/guides/...\n")
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for doc_file in reorganization_docs:
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src = root / doc_file
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dest = target_dir / doc_file
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if src.exists():
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if dest.exists():
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print(f"⚠ 跳过: {doc_file} (目标位置已存在)")
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else:
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try:
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shutil.move(str(src), str(dest))
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print(f"✓ 已移动: {doc_file} -> docs/guides/")
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moved_count += 1
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except Exception as e:
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print(f"✗ 移动失败: {doc_file} - {e}")
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else:
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print(f"ℹ 不存在: {doc_file}")
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print(f"\n✅ 移动完成!")
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print(f" - 已移动: {moved_count} 个文件")
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print(f"\n📌 这些文档现在位于: docs/guides/")
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if __name__ == "__main__":
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move_reorganization_docs()
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